Manufacturing Cost

mathdad

Full Member
Joined
Apr 24, 2015
Messages
925
See attachment. I think this is a plug and chug problem. Yes? If so, piece of cake.
 

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What is your attempt?

-Dan
My effort:

C = 4000 + 2x

Let x = 1000 watches

C = 4000 + 2(1000)

C = 4000 + 2000

C = $6000

The cost of producing 1000 watches is $6000.

Now let x = 2000 watches

C = 4000 + 2(2000)

C = 4000 + 4000

C = $8000

The cost of producing 2000 watches is $8000.

You say
 
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