See attachment. I think this is a plug and chug problem. Yes? If so, piece of cake.
mathdad Full Member Joined Apr 24, 2015 Messages 925 Sep 5, 2024 #1 See attachment. I think this is a plug and chug problem. Yes? If so, piece of cake. Attachments 20240905_103804.jpg 382.6 KB · Views: 4
topsquark Senior Member Joined Aug 27, 2012 Messages 2,307 Sep 5, 2024 #2 mathdad said: See attachment. I think this is a plug and chug problem. Yes? If so, piece of cake. Click to expand... What is your attempt? -Dan
mathdad said: See attachment. I think this is a plug and chug problem. Yes? If so, piece of cake. Click to expand... What is your attempt? -Dan
mathdad Full Member Joined Apr 24, 2015 Messages 925 Sep 6, 2024 #3 topsquark said: What is your attempt? -Dan Click to expand... My effort: C = 4000 + 2x Let x = 1000 watches C = 4000 + 2(1000) C = 4000 + 2000 C = $6000 The cost of producing 1000 watches is $6000. Now let x = 2000 watches C = 4000 + 2(2000) C = 4000 + 4000 C = $8000 The cost of producing 2000 watches is $8000. You say
topsquark said: What is your attempt? -Dan Click to expand... My effort: C = 4000 + 2x Let x = 1000 watches C = 4000 + 2(1000) C = 4000 + 2000 C = $6000 The cost of producing 1000 watches is $6000. Now let x = 2000 watches C = 4000 + 2(2000) C = 4000 + 4000 C = $8000 The cost of producing 2000 watches is $8000. You say