Making sure

[swag312]

In 2000 the company had 300 customers. In 2015, this company already had
1200 customers. How many customers did the company have in 2008 if we know that
the number of customers growing is linear?

Just want to make sure, is 780 the correct answer?

 

[MarkFL]

If the number of customers is growing linearly, then we must have:

[MATH]\frac{C(2008)-C(2000)}{2008-2000}=\frac{C(2015)-C(2000)}{2015-2000}[/MATH]
[MATH]\frac{C(2008)-300}{8}=\frac{1200-300}{15}=60[/MATH]
[MATH]C(2008)=60\cdot8+300=780\quad\checkmark[/MATH]
Yes, I agree with your result.

 

[swag312]

If the number of customers is growing linearly, then we must have:

[MATH]\frac{C(2008)-C(2000)}{2008-2000}=\frac{C(2015)-C(2000)}{2015-2000}[/MATH]
[MATH]\frac{C(2008)-300}{8}=\frac{1200-300}{15}=60[/MATH]
[MATH]C(2008)=60\cdot8+300=780\quad\checkmark[/MATH]
Yes, I agree with your result.

Thank you very much for confirming it!