Make y=mx+b with y+1/2 = -1/3 (x+ 1/2)

[taragbeh]

This is hard but please let me know if I am on the rght track and if my answer is correct

y+1/2 = -1/3 (x+ 1/2)

y + 1/2 = -1/3x -2/6 (multiply and remove th braccket)

y = 1/3x - 2/6 - 1/2 (subtract 1/2 from both sides)

y= 1/3x - 5/6, therefore Y=mx+b

 

[stapel]

This is hard but please let me know if I am on the rght track and if my answer is correct

What was the actual question? (You begin your post with a line equation, and then manipulate it, but was that equation the beginning of the exercise? What were the instructions?)

...therefore Y=mx+b

How does this relate? What were you supposed to prove, that you ended up with the above "therefore" statement?

Please be complete. Thank you!

Eliz.

 

[taragbeh]

Re:

What was the actual question? ...What were the instructions?

The question is y + 1/2 = -1/3(x + 1/2)

Solving a variable so that y=mx+b

 

[tkhunny]

Re: Make y=mx+b

y+1/2 = -1/3 (x+ 1/2)

y + 1/2 = -1/3x -2/6

You went astray right off. (1/3)(1/2) = 1/6

 

[taragbeh]

Re: Make y=mx+b

y+1/2 = -1/3 (x+ 1/2)

y + 1/2 = -1/3x -2/6

You went astray right off. (1/3)(1/2) = 1/6

Can you show me the steps from the beginning to the end. this one is abig confusing and tricky. Thanks

 

[skeeter]

Re: Make y=mx+b

\(\displaystyle y + \frac{1}{2} = -\frac{1}{3} \left(x + \frac{1}{2} \right)\)

distribute the -1/3 on the right side ...

\(\displaystyle y + \frac{1}{2} = -\frac{1}{3}x - \frac{1}{6}\)

subtract 1/2 from both sides ...

\(\displaystyle y = -\frac{1}{3}x - \frac{2}{3}\)