lmarshall1995
New member
- Joined
- Jan 28, 2020
- Messages
- 6
Hi,
I have the below question:
A maintenance engineer, reading off a strain gauge attached at position B of the beam, obtained the x-axis strain, ?? = 1.7*10^-5 in the beam. If the steel beam has a rectangular cross-sectional of width, w = 50 mm and height, h = 100 mm, calculate the tension, T in the cable that ensures the structure is in equilibrium. Assume the beam behaves in a linear elastic manner with ? = ??. For the steel material, take the Young Modulus, E = 210 GPa.
I have figured out the deflection at B is:
wL^4
8EI
I= bh^3
12
I = (50*10^-3)*(100*10^-3)^3 = 4.167*10^-6 m^4 OR 4.167*10^6 mm^4
12
(3*10^3) * 2^4 = 6.857 * 10^-3 m
8*(210*10^9)*I
So the deflection is 6.857 mm.
How do I go about making this beam in equilibrium with the 20degree cable using the x-axis strain?
Thank you
I have the below question:
A maintenance engineer, reading off a strain gauge attached at position B of the beam, obtained the x-axis strain, ?? = 1.7*10^-5 in the beam. If the steel beam has a rectangular cross-sectional of width, w = 50 mm and height, h = 100 mm, calculate the tension, T in the cable that ensures the structure is in equilibrium. Assume the beam behaves in a linear elastic manner with ? = ??. For the steel material, take the Young Modulus, E = 210 GPa.
I have figured out the deflection at B is:
wL^4
8EI
I= bh^3
12
I = (50*10^-3)*(100*10^-3)^3 = 4.167*10^-6 m^4 OR 4.167*10^6 mm^4
12
(3*10^3) * 2^4 = 6.857 * 10^-3 m
8*(210*10^9)*I
So the deflection is 6.857 mm.
How do I go about making this beam in equilibrium with the 20degree cable using the x-axis strain?
Thank you