Magic H: use 1 thru 13 in three 5-entry rows, w/ rows, corne

[turtle]

Hi! Can anyone help us? We are trying to solve a Magic H problem. You use the numbers 1 thru 13 and put them in an H the has 5 numbers down, 5 across and 5 down the other side. You can only use each number once. But, all lines and all 4 corners have to equal the same number. Please anyone that can help us....this is driving us crazy.

 

[stapel]

You use the numbers 1 thru 13 and put them in an H the has 5 numbers down, 5 across and 5 down the other side. You can only use each number once. But, all lines and all 4 corners have to equal the same number.

There is, to my knowledge, no formula for this. You just have to try various arrangements. But since the sum of the numbers from 1 through 13 is 91, and you'll be using two of the numbers twice, then your total for all three rows is somewhere between 91 + 1 + 2 = 94 and 91 + 12 + 13 = 116. This puts the sum of any row between 94/3 = 31.3... and 116/3 = 38.6.... Reasonably, the row-sum will be between 32 and 38.

Work from there. Have fun!

Eliz.

 

[Denis]

Geezzz...there's close to 500 solutions :shock:

2 examples (left H line : horizontal H line : right H line) :

1,2,5,12,13 : 5,6,8,11,3 : 9,4,3,7,10 ; sums = 33

6,7,5,8,10 : 5,2,4,13,12 : 9,1,12,3,11 ; sums = 36

 

[turtle]

Denis~
Thank you very much!!! I suck at math!!!