I am having problems with the fraction part of this equation.
B Brandysmom New member Joined Aug 28, 2007 Messages 8 Aug 28, 2007 #1 I am having problems with the fraction part of this equation.
pka Elite Member Joined Jan 29, 2005 Messages 11,976 Aug 28, 2007 #2 \(\displaystyle \begin{array}{rcl} \frac{m}{5} + 8 & = & - 7 \\ \frac{m}{5} & = & - 7 - 8 \\ \frac{m}{5} & = & - 15 \\ m & = & - 75 \\ \\ \end{array}\)
\(\displaystyle \begin{array}{rcl} \frac{m}{5} + 8 & = & - 7 \\ \frac{m}{5} & = & - 7 - 8 \\ \frac{m}{5} & = & - 15 \\ m & = & - 75 \\ \\ \end{array}\)
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Aug 28, 2007 #3 Mom, remember that if a/b = c/d, then ad = bc ; crisscross multiplication If you have a/b = c, same thing: a/b = c/1; so a(1) = bc, a = bc Same with m/5 = -15 ; m/5 = -15/1 : m(1) = 5(-15) : m = -75 Yokay?
Mom, remember that if a/b = c/d, then ad = bc ; crisscross multiplication If you have a/b = c, same thing: a/b = c/1; so a(1) = bc, a = bc Same with m/5 = -15 ; m/5 = -15/1 : m(1) = 5(-15) : m = -75 Yokay?
