brentwoodbc
New member
- Joined
- May 8, 2009
- Messages
- 18
I think I get it but I'm not sure Im doing this right.
on a lottery you can pick 3 of 10 numbers between 0-9 "randomly drawn" the 3 numbers can be the same.
A. what are the odds of getting the 3 numbers, and them being in the same order as drawn.
so I did 10x10x10 because it could be 1/10 3 times so =1000 (correct)
B. this is the one that's giving me trouble.
What are the odds of winning if they can be in any order?
answer is 167.
I know 1000/6 (6 could be 3!) is roughly 167 but I dont know know if thats the right way to do it, or why to do it that way....
I thought it would be 3/10 haha.
I also wanted to know how the two answer's would be changed if they couldnt be the same number. I assume that in part (A) it would be 0x9x8= 1/720 but for part be Im still confused.
thanks.
on a lottery you can pick 3 of 10 numbers between 0-9 "randomly drawn" the 3 numbers can be the same.
A. what are the odds of getting the 3 numbers, and them being in the same order as drawn.
so I did 10x10x10 because it could be 1/10 3 times so =1000 (correct)
B. this is the one that's giving me trouble.
What are the odds of winning if they can be in any order?
answer is 167.
I know 1000/6 (6 could be 3!) is roughly 167 but I dont know know if thats the right way to do it, or why to do it that way....
I thought it would be 3/10 haha.
I also wanted to know how the two answer's would be changed if they couldnt be the same number. I assume that in part (A) it would be 0x9x8= 1/720 but for part be Im still confused.
thanks.