Lost with this Calculus problem

[mariok47]

Haven't taken Calculus since high school, and boyfriend (math nerd) wrote me a note using Calculus equations. I think I'm just too far removed from Calculus to figure it out!

First Term
sqrt -1 (obviously, "i")


Second Term
λ

<a,b>Σ


Third Term
∫du - c (I think that this should solve to "u", but my limited abilities solve this to u^2/2....??)


I'm thinking, that because the first term is "i" and the last term might be "u", that the complicated middle equation somehow results in "love"?

Any help would be greatly appreciated!

 

[MarkFL]

I would guess for the middle "word," he is letting:

\(\displaystyle \lambda\) = L

\(\displaystyle \lim_{x\to\infty}\dfrac{1}{x}=0\) = O

\(\displaystyle \langle a,b \rangle\) = vector = V

\(\displaystyle \Sigma\) = E

For e, I might have used \(\displaystyle \lim_{n\to\infty}\left(\left(1+\dfrac{1}{n} \right)^n \right)\)

 

[JeffM]

Haven't taken Calculus since high school, and boyfriend (math nerd) wrote me a note using Calculus equations. I think I'm just too far removed from Calculus to figure it out!

First Term
sqrt -1 (obviously, "i")


Second Term
λ

<a,b>Σ


Third Term
∫du - c (I think that this should solve to "u", but my limited abilities solve this to u^2/2....??) Your INTUITION is correct, not your math recollection. So

\(\displaystyle \int du = u + c \implies \int du - c = u + c - c = u.\)


I'm thinking, that because the first term is "i" and the last term might be "u", that the complicated middle equation somehow results in "love"?

Any help would be greatly appreciated!

.