looking for where can i learn this problems of numerical analysis (specifically problem 2)

For (2) what are \displaystyle \nabla and Δ\displaystyle \Delta? How are they defined in your text book?
 
its nabla and delta
i couldn't find any definition
i dont even understand what thay are !
 
Are you taking a course? Do you have a textbook? What about a teacher? "Nabla" is defined here: Nabla -- from Wolfram MathWorld .

Nabla, \displaystyle \nabla, is a "differential operator" that, in an xy-coordinate system is x+y\displaystyle \frac{\partial}{\partial x}+ \frac{\partial}{\partial y} and in an xyz-coordinate system is x+y+z\displaystyle \frac{\partial}{\partial x}+ \frac{\partial}{\partial y}+ \frac{\partial}{\partial z}.

For example, f(x,y,z)\displaystyle \nabla f(x,y,z) where f is a scalar valued of x, y, and z is fx+fy+fz\displaystyle \frac{\partial f}{\partial x}+ \frac{\partial f}{\partial y}+ \frac{\partial f}{\partial z} (called "grad f", "gradient of f") and is the vector that points in the direction of fastest increase of f and has length the rate of increase (derivative) in that direction.

Or, if f=f1(x,y,z)i+f2(x,y,z)j+f3(x,y,z)k\displaystyle \vec{f}= f_1(x,y,z)\vec{i}+ f_2(x,y,z)\vec{j}+ f_3(x,y,z)\vec{k} is a vector valued function the "dot product" of \displaystyle \nabla and f\displaystyle \vec{f}, f=f1x+f2y+f3z\displaystyle \nabla\cdot \vec{f}= \frac{\partial f_1}{\partial x}+ \frac{\partial f_2}{\partial y}+ \frac{\partial f_3}{\partial z} (called "div f", divergence), measures how fast the vector functions spreads out. Finally, the cross product of \displaystyle \nabla and f=(f2zf3f2z)i+(f3xf1z)j+(f1yf2x)k\displaystyle \vec{f}= \left(\frac{\partial f_2}{\partial z}- \frac{\partial f_3}{\partial f_2}{\partial z}\right)\vec{i}+ \left(\frac{\partial f_3}{\partial x}- \frac{\partial f_1}{\partial z}\right)\vec{j}+ \left(\frac{\partial f_1}{\partial y}- \frac{\partial f_2}{\partial x}\right)\vec{k}. The "curl" measures the rotation of the vector field.

Δ\displaystyle \Delta is much simpler. In introductory Calculus Δx\displaystyle \Delta x is used to mean a small change in x. For example, the derivative of y(x) can be defined by dydx=\displaystyle \frac{dy}{dx}= limΔx0ΔyΔx\displaystyle \lim_{\Delta x \to 0}\frac{\Delta y}{\Delta x}=limΔx0y(x+Δx)y(x)Δx\displaystyle = \lim_{\Delta x\to 0}\frac{y(x+\Delta x)- y(x)}{\Delta x}. That is, Δx\displaystyle \Delta x is a small change in x and Δy\displaystyle \Delta y is a small change in y, the change from y(x)\displaystyle y(x) to y(x+Δx)\displaystyle y(x+ \Delta x).
 
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i am really bad at math (really bad might be an understatement) but i want to learn
but couldn't get the courage to learn from the beginning.. because i have start from high school again.
Are you taking a course >>> yes (BSC in CSE)
Do you have a textbook >>> yes (Numerical Analysis Richard L. Burden, J. Douglas Faires, Annette M. Burden)
What about a teacher? >>> yes but too busy.... and cant access other resources because of covid.
i took some notes from class.
i understood what my teacher taught me but when it come to solve anything i just cant.
but i feel like somethings missing that i should have known from the start.
but i don't know what.
i feel so lost and the shear amount of things i have to learn just freezes me.
if i am not climbing i am falling.
 

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