solve: log_{\sqrt{6}}(x-1)+log_{6} x^2=lg125+3lg2-1
1 123 New member Joined Nov 6, 2010 Messages 46 Apr 9, 2011 #1 solve: log6(x−1)+log6x2=lg125+3lg2−1\displaystyle log_{\sqrt{6}}(x-1)+log_{6} x^2=lg125+3lg2-1log6(x−1)+log6x2=lg125+3lg2−1
solve: log6(x−1)+log6x2=lg125+3lg2−1\displaystyle log_{\sqrt{6}}(x-1)+log_{6} x^2=lg125+3lg2-1log6(x−1)+log6x2=lg125+3lg2−1
tkhunny Moderator Staff member Joined Apr 12, 2005 Messages 11,339 Apr 9, 2011 #2 Become accustomed to a quick transformation, not this specific one, but all like it. logan(x)=log(x)log(an)=log(x)n⋅log(a)=1n⋅loga(x)\displaystyle log_{a^n}(x) = \frac{log(x)}{log(a^{n})} = \frac{log(x)}{n\cdot log(a)} = \frac{1}{n}\cdot log_{a}(x)logan(x)=log(an)log(x)=n⋅log(a)log(x)=n1⋅loga(x) You tell me what this has to do with your homework assignment.
Become accustomed to a quick transformation, not this specific one, but all like it. logan(x)=log(x)log(an)=log(x)n⋅log(a)=1n⋅loga(x)\displaystyle log_{a^n}(x) = \frac{log(x)}{log(a^{n})} = \frac{log(x)}{n\cdot log(a)} = \frac{1}{n}\cdot log_{a}(x)logan(x)=log(an)log(x)=n⋅log(a)log(x)=n1⋅loga(x) You tell me what this has to do with your homework assignment.
