Logarithms

[Letha]

I need help with this problem 5-2e^(x+1)=1 I am not sure how to start?

 

[mmm4444bot]

You want to isolate the power of e, so that you can switch to logarithmic form.

Start adding/subtracting/multiplying/dividing both sides by whatever needed (in the usual way) so that you get the following:

e^(x + 1) = everything else

Then, take the natural logarithm of both sides.

 

[stapel]

I am not sure how to start?

To learn how to solve exponential equations, try here. :wink: