Logarithms: solve log_6n=3/4log_616

wind

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Sep 20, 2006
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Hi, I need help with this question

solve...

\(\displaystyle \L\\\log_{6}n=\) \(\displaystyle \L\\\frac{3}{4}log_{6}16\)
.
.
\(\displaystyle \L\\\ n=\) \(\displaystyle \L\\\frac{{0.75}log_{6}16}{log_{6}}\)

Do the \(\displaystyle \L\\\ log_{6}\) cancel out?

n=12?
 
wind said:
Hi, I need help with this question

solve...

\(\displaystyle \L\\\log_{6}n=\) \(\displaystyle \L\\\frac{3}{4}log_{6}16\)
.
.
\(\displaystyle \L\\\ n=\) \(\displaystyle \L\\\frac{{0.75}log_{6}16}{log_{6}}\)

Do the \(\displaystyle \L\\\ log_{6}\) cancel out?

n=12?
\(\displaystyle \mbox{ \log_6}\) is an operation, not a number. Care to have a rethink?
 
\(\displaystyle \L \log_6{n} = \frac{3}{4}\log_6{16}\)

\(\displaystyle \L \log_6{n} = \log_6{16^{ \frac{3}{4}}}\)

note ... if log(a) = log(b), then a = b

\(\displaystyle \L n = 16^{ \frac{3}{4}} = 8\)
 
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