LOGARITHMS ( HELP )

[JOSH BAR]

Use logarithms to solve the equation. (Round the answer to four decimal places.)
7(1.08^3x + 1) = 14

X=____


I thought the answer was 2.6667 but I was counted wrong. Any other answer?

 

[Loren]

As written "7(1.08^3x + 1) = 14" actually means $\displaystyle 7(1.08^3 x + 1) = 14$.

I think you mean 7(1.08^(3x) + 1) = 14 which means $\displaystyle 7(1.08^{3x} + 1) = 14$.

Or do you mean 7(1.08^(3x + 1)) = 14 which means $\displaystyle 7(1.08^{3x + 1}) = 14$?

To be more specific you need to use parenthesis. Why don't you show us your work so we can see where you went wrong?

 

[JOSH BAR]

I actually just figured it out. The answer is 2.6688. I was off on the rounding. Thanks for the help anyway.

 

[BigGlenntheHeavy]

$\displaystyle 7(1.08^{3x}+1) \ = \ 14$

$\displaystyle By \ inspection \ it \ should \ be \ obvious \ that \ x \ = \ 0.$

 

[JOSH BAR]

$\displaystyle 7(1.08^{3x}+1) \ = \ 14$

$\displaystyle By \ inspection \ it \ should \ be \ obvious \ that \ x \ = \ 0.$

Its actually not that problem, it is the 3rd on listed.

7(1.08^(3x+1))=14