Logarithms Help -> LOG A/ cube root of BC^2

[timpickens]

LOG A/ cube root of BC^2

I'm not sure if I'm doing this right, but so far I've got:

1/3 Log A/BC^2

1/3 (Log A - Log BC^2)

Thank you!

 

[stapel]

What are the instructions? Are you supposed to expand? Evaluate? Or something else?

What all is inside the log? Do you mean "log(a/cbrtc²)", "log_a(cbrtc²)", or something else?

Thank you.

Eliz.