Logarithmn equation

[Levornia]

Log[base 5] 1/125 = x

I am to solve. Honestly I don't know where to start...I know the formulas and I have studied but this just doesn't make since to me. Please help

 

[BigGlenntheHeavy]

\(\displaystyle log_5\bigg(\frac{1}{125}\bigg) \ = \ x\)

\(\displaystyle log_5\bigg(\frac{1}{5^3}\bigg) \ = \ x\)

\(\displaystyle log_5(5^{-3}) \ = \ x\)

\(\displaystyle Ergo, \ 5^{-3} \ = \ 5^x, \ x \ = \ -3\)