logarithmic question

[math321]

this is the last question i got to do
need some help urgently

Solve the equation.
(16/9)^(x-1) = (3/4)^(x-1)

 

[math321]

reach as far as here

WHERE DO I GO FROM HERE

 

[wjm11]

Solve the equation.
(16/9)^(x-1) = (3/4)^(x-1)

(16/9)^(x-1) = (9/16)^-(x-1) = (9/16)^(1-x) = ((3/4)^2)^(1-x) = (3/4)^(2(1-x))

(3/4)^(2(1-x)) = (3/4)^(x-1)

2(1-x) = (x-1)
2-2x = x-1
3 = 3x
x = 1

 

[math321]

thanks alot lad