logarithmic question

math321

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Joined
Nov 18, 2010
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9
can anyone please help with this question

Code:
log (3x) = log 4 + log (x - 1)
 
That is equivalent to log(4x43x)=0\displaystyle \log \left( {\frac{{4x - 4}}{{3x}}} \right) = 0.
 
and then wat
can u jus break it down a little simpler for me please

thank you
 
pka said:
That is equivalent to log(4x43x)=0\displaystyle \log \left( {\frac{{4x - 4}}{{3x}}} \right) = 0.

math321,

this is equivalent to \(\displaystyle \log_{10} \left({\frac{{4x - 4}}{3x}}} \right) = 0\)


Change this equation to its equivalent exponential form:

100 = 4x43x\displaystyle 10^0 \ = \ \frac{4x - 4}{3x}

1 = 4x43x\displaystyle 1 \ = \ \frac{4x - 4}{3x}


Solve for x,\displaystyle x, but you must check those candidate solutions in the original equation.
 
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