LOGARITHMIC INEQUALITY

[achi_kun]

I don’t know how the solution works with this one.

 

[Deleted member 4993]

View attachment 22669

I don’t know how the solution works with this one.

If I were to do this problem, I would use the fact:

log_n(n) = 1

Please show us what you have tried and exactly where you are stuck.

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Please share your work/thoughts about this problem.

 

[pka]

If I were to do this I would rewrite it as $\dfrac{\log(3x-1)}{\log(7)}>1$. Recall that the logarithm is one-to-one.

 

[skeeter]

[MATH]\log_7(7) = 1 \implies \log_7(3x-1) > 1 \text{ if ... ?}[/MATH]