logarithmic correct?

[shaylee112]

1. Convert the following equations into logarithmic form:

a. 9 = 4x
log(9) = log(4x)
2log(3) = log4 + log(x)

b. 3 = 6y
log(3) = log(2) + log3 + log(y)
0 = log(2) + log(y)

c. 5 = 7y
log(g) = log(7) + log(y)


d. X = 9y
log(x) = 2log(3) + log(y)

 

[stapel]

You have posted these equations as being linear. For instance, (1) is "9 = 4x". But "log form" usually refers to exponential equations, such as "9 = 4^x".

Are these really linear? (It's extremely unusual, is why I ask.)

Thank you.

Eliz.

 

[shaylee112]

Ummm...

well It is written 9=4^x the x is lifted but I can't type it that way[/tex][/code]

 

[stapel]

Re: Ummm...

It is written 9=4^x

In the book? Because it isn't that way in your first post...?

So you mean the equation for (1) isn't "9 = 4x", but "9 = 4^x". But then why use the multiplication-to-addition log rule? Didn't they give you a "power-to-multiplier" rule? Something like "log_b(aⁿ) = n×log_b(a)"?

And are you supposed to be using log rules to solve for a variable or something, or are you just supposed to be converting the one form of the equation to the other, so "y = b^x" becomes "x = log_b(y)"?

Eliz.

 

[shaylee112]

directions say

Convert the following equations into logarithmic form:

9=4x but the x is raised in the air I just don't know how to show that liek you did in your previous post. 9 = 4x

 

[Gene]

Reread what Staple said about powers.
9 = 4^x = 4^x
that is two different ways of writing exponents. To use the first way you type
4 < sup > x < /sup >
without the spaces, all scrunched together but it doesn't matter which way you do it. They mean the same thing.
log(9) = 4*log(x)
That is how powers work. Not like multiplication as you did it.
x = log₄(9)
To write that you type
log < sub > 4 < /sub >
without the spaces, all scrunched together.

You can check to see if you are doing it correctly by clicking on PREVIEW.

 

[shaylee112]

Convert the following equations into logarithmic form:

9=4<sup>x