Logarithm

[usawhney]

a) log[sub:2kwerc7t]2[/sub:2kwerc7t] (x+3) + log[sub:2kwerc7t]2[/sub:2kwerc7t] (x-3)=4
b) 5(3[sup:2kwerc7t]2x+4)[/sup:2kwerc7t]=60

 

[stapel]

a) log[sub:3g4tiorr]2[/sub:3g4tiorr] (x+3) + log[sub:3g4tiorr]2[/sub:3g4tiorr] (x-3)=4
b) 5(3[sup:3g4tiorr]2x+4)[/sup:3g4tiorr]=60

You don't provide any instructions; I'll guess you're supposed to "solve and check".

You don't show any work, so I'll guess you need lessons first. Try log lessons and exponential lessons.

Once you've learned the basics, please attempt the exercises. If you get stuck, you can then reply with a clear listing of your steps and reasoning so far. Thank you! :wink: