learningmathh
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- Oct 25, 2014
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- 31
Y= 77,9*lgx-216,4=760
My take:lgx=760+216,4/77,9
10^lgx=10^(760+216,4)/77,9
What is wrong here??
My take:lgx=760+216,4/77,9
10^lgx=10^(760+216,4)/77,9
What is wrong here??
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Logarithm problem
- Thread starter learningmathh
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Y= 77,9*lgx-216,4=760
My take:lgx=760+216,4/77,9
10^lgx=10^(760+216,4)/77,9
What is wrong here??
I cannot tell what is wrong - because you did not tell us what you wanted to calculate!
Y= 77,9*lgx-216,4=760
My take:lgx=760+216,4/77,9
10^lgx=10^(760+216,4)/77,9
What is wrong here??
Assuming this is
Y= 77,9 log(x) - 216,4 = 760
and you want the value of x, nothing is wrong so far [but you could use grouping symbols like parenthesis and brackets to make it less ambiguous]. It's when you get to the next step of converting 10log(x) to x where you might get in trouble. 10log(x) is equal to x only if the log is base 10.