NoGoodAtMath
New member
- Joined
- May 2, 2013
- Messages
- 35
The directions say to solve the equation. Write the solution set with the exact solutions. Also give approximate solutions to 4 decimal places.
log8(3y-5)+10=12
I'm not sure how to start this problem. The way I attempted this problem was to subtract 10 from both sides, which gave me log8(3y-5)=2. Then I moved the log8 and used it like this (3y-5)^8=2. But I don't think any of that is correct. Could someone help? Thanks.
log8(3y-5)+10=12
I'm not sure how to start this problem. The way I attempted this problem was to subtract 10 from both sides, which gave me log8(3y-5)=2. Then I moved the log8 and used it like this (3y-5)^8=2. But I don't think any of that is correct. Could someone help? Thanks.
