ln (5+4x) - ln (3+x) = ln3
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Nov 13, 2005 #2 This one works just like the other ones you've posted, and by the same reasoning and rules that the other tutors have explained and demonstrated: 1) Apply log rules to combine terms to get "log(something) = log(something else)". 2) Set "something" equal to "something else". 3) Solve. Please reply showing how far you have gotten and where you are stuck. Please be specific. Thank you. Eliz.
This one works just like the other ones you've posted, and by the same reasoning and rules that the other tutors have explained and demonstrated: 1) Apply log rules to combine terms to get "log(something) = log(something else)". 2) Set "something" equal to "something else". 3) Solve. Please reply showing how far you have gotten and where you are stuck. Please be specific. Thank you. Eliz.
O ocgirl83 New member Joined Sep 3, 2005 Messages 39 Nov 13, 2005 #3 i get that it would be (5+4x/ 3+x) = 3 but i dont know what the quotient would be, that is where i am having problems.
i get that it would be (5+4x/ 3+x) = 3 but i dont know what the quotient would be, that is where i am having problems.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Nov 13, 2005 #4 ocgirl83 said: i get that it would be (5+4x/ 3+x) = 3... Click to expand... So you have: . . . . .\(\displaystyle \Large{\frac{5\mbox{ }+\mbox{ }4x}{3\mbox{ }+\mbox{ }x}=\frac{3}{1}}\) (I'm pretty sure that's what you meant, anyway.) So cross-multiply as usual: . . . . .\(\displaystyle \large{1(5\mbox{ }+\mbox{ }4x)\mbox{ }=\mbox{ }3(3\mbox{ }+\mbox{ }x)}\) Then solve the linear equation by the usual methods. Remember to check your solution in the original equation, to make sure it works. Eliz.
ocgirl83 said: i get that it would be (5+4x/ 3+x) = 3... Click to expand... So you have: . . . . .\(\displaystyle \Large{\frac{5\mbox{ }+\mbox{ }4x}{3\mbox{ }+\mbox{ }x}=\frac{3}{1}}\) (I'm pretty sure that's what you meant, anyway.) So cross-multiply as usual: . . . . .\(\displaystyle \large{1(5\mbox{ }+\mbox{ }4x)\mbox{ }=\mbox{ }3(3\mbox{ }+\mbox{ }x)}\) Then solve the linear equation by the usual methods. Remember to check your solution in the original equation, to make sure it works. Eliz.