"Solve the equation 2log2 x - log2(x+3) = 2 Any help would be appreciated!
R Ryan.Morris New member Joined Jan 23, 2014 Messages 1 Jan 23, 2014 #1 "Solve the equation 2log2 x - log2(x+3) = 2 Any help would be appreciated!
D Deleted member 4993 Guest Jan 23, 2014 #2 Ryan.Morris said: "Solve the equation 2log2 x - log2(x+3) = 2 Any help would be appreciated! Click to expand... Use laws of logarithms such as: Loga(b^c) = c* Loga(b) etc. Please share your work with us . If you are stuck at the beginning tell us and we'll start with the definitions. You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL: http://www.freemathhelp.com/forum/th...Before-Posting!
Ryan.Morris said: "Solve the equation 2log2 x - log2(x+3) = 2 Any help would be appreciated! Click to expand... Use laws of logarithms such as: Loga(b^c) = c* Loga(b) etc. Please share your work with us . If you are stuck at the beginning tell us and we'll start with the definitions. You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL: http://www.freemathhelp.com/forum/th...Before-Posting!
J JeffM Elite Member Joined Sep 14, 2012 Messages 7,872 Jan 23, 2014 #3 Ryan.Morris said: "Solve the equation 2log2 x - log2(x+3) = 2 Any help would be appreciated! Click to expand... If you can't get started, here is a hint. \(\displaystyle log_a(b) = log_a(c) \iff b = c.\) The main problem here is that you do not have logs to the same base on both sides of the equation. How might you rectify that? Last edited by a moderator: Jan 23, 2014
Ryan.Morris said: "Solve the equation 2log2 x - log2(x+3) = 2 Any help would be appreciated! Click to expand... If you can't get started, here is a hint. \(\displaystyle log_a(b) = log_a(c) \iff b = c.\) The main problem here is that you do not have logs to the same base on both sides of the equation. How might you rectify that?