Log question- need help

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Slipery

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Jan 11, 2008
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Hey guys.. Sorry, I couldn't find the right forum to put this in.
I have a log question that I am working on for something I need to hand in today..

I have the answer, I was helped by someone, I am just having trouble understanding a step in the answer, and I don't really want to just move on without being able to grasp whats happening.

Here is the question:

Image of Logs question - Photobucket - Video and Image Hosting

I felt this would be faster then to write it out..
I am wondering what is happening in the 3rd to 4th step mainly.. how does the -1 exponent become -3/2, and what happened to the square root sign and how did that interact?

Thanks alot
 


Raising to the power of 1/2 is the same as taking the square root.

sqrt(x) = x^(1/2)

[sqrt(x)]^3 = [x^(1/2)]^3 = x^(3/2)

1/[sqrt(x)]^3 = x^(-3/2)

 
Slipery said:
Hey guys.. Sorry, I couldn't find the right forum to put this in.
I have a log question that I am working on for something I need to hand in today..

I have the answer, I was helped by someone, I am just having trouble understanding a step in the answer, and I don't really want to just move on without being able to grasp whats happening.

Here is the question:

Image of Logs question - Photobucket - Video and Image Hosting

I do not see an image - or URL

I felt this would be faster then to write it out..
I am wondering what is happening in the 3rd to 4th step mainly.. how does the -1 exponent become -3/2, and what happened to the square root sign and how did that interact?

Thanks alot
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