log help

[Rudy]

The problem is log (logx) = 2
so taking the exp form: 10^2 = log X then....taking it again: 10^100 = X???? Is this correct?

 

[Denis]

The problem is log (logx) = 2

log (logx) = 2
log(x) = e^2
x = e^(e^2) : ~1618.178

 

[soroban]

Hello, Rudy!

$\displaystyle \text{Solve: }\;\log (\log x) \:=\: 2$

$\displaystyle \text{so taking the exp form: }\:\log x\:=\:10^2$

$\displaystyle \text{taking it again: }x \:=\:10^{100}$

$\displaystyle \text{Is this correct?}$

$\displaystyle \text{Since }log\text{ (with no subscript) usually means "base 10"}$

. . $\displaystyle Y\!es!\:\text{ . . . You are correct!}$