Log equation C=B*LogR + A*R, solve for R

DeltaBlues

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Log equation C=B*LogR + A*R, solve for R

Been poking at this and have not been successful at a solution. Having R in a simple term and in a log is throwing me.

Appreciate any help
 
Kwickie (watching hockey game!); I got to:
e^[(c-ar) / b] = r ; iteration required

Edit: Or 10^[(c-ar) / b] = r if you're using Log instead of Ln
 
DeltaBlues said:
Log equation C=B*LogR + A*R, solve for R

Been poking at this and have not been successful at a solution. Having R in a simple term and in a log is throwing me.

Appreciate any help

Like Dennis indicated above, I do not see any analytical closed-form solution.

If you know the values of A, B & C, you can do this graphically or by numerical methods (both are approximations).
 
Thanks guys for the help, much appreciated.

Good to learn I wasn't completely in the woods as well.

Dan
 
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