log and ln e^(3x-1)=17 I have no idea what to do.
- Thread starter kmarkwell
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pka
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For part a.
\(\displaystyle e^{\left( {3x - 1} \right)} = 17\; \Rightarrow \;\left( {3x - 1} \right) = \ln (17).\)
For part b, we assume that LOG is base 10, (though some texts use that for LN).
\(\displaystyle LOG\left( {4x - 3} \right) = 2.1\; \Rightarrow \;\left( {4x - 3} \right) = 10^{2.1}.\)
\(\displaystyle e^{\left( {3x - 1} \right)} = 17\; \Rightarrow \;\left( {3x - 1} \right) = \ln (17).\)
For part b, we assume that LOG is base 10, (though some texts use that for LN).
\(\displaystyle LOG\left( {4x - 3} \right) = 2.1\; \Rightarrow \;\left( {4x - 3} \right) = 10^{2.1}.\)