ln problem - # 4

[Jason76]

\(\displaystyle 3\ln(2)+ 2\ln(3) = ?\)

 

[Steven G]

\(\displaystyle 3\ln(2)+ 2\ln(3) = ?\)

And your attempt is...
Can you please list ALL the rules for logs?

 

[Deleted member 4993]

\(\displaystyle 3\ln(2)+ 2\ln(3) = ?\)

Jason,

Last time when you were in this forum - you were doing integration (calculus)?

You really don't know how to do this?

The laws of logarithm that you need to use is:

log(a^b) = b * log(a) ... and...

log(x * y) = log(x) + log(y)

Now we need to see your attempts (you know the rules).

 

[Jason76]

\(\displaystyle 3\ln(2) + 2\ln(3) = (\ln(2) * \ln(3))\) using log rules but what about the coefficients?

 

[Deleted member 4993]

\(\displaystyle 3\ln(2)+ 2\ln(3) = ?\)

\(\displaystyle 3\ln(2)+ 2\ln(3) = ln(2^3) + ln(3^2) = ln(8*9) = ln(72)\)

Jason, did you forget all of the log rules and associated algebra????