so if I write it in slope-intercept form I get y = -(z+5)x/(z-3) + 8/(z-3) right? and the slopes of parallel lines are the same aren't they?Write the line in the slope-intercept form: [imath]y=mx+b[/imath].
What do you know about the slopes of parallel lines?
I'm sorry for posting with no work I'm a tutor who's trying to understand how this problem goes to better understand how to help my student.If a line is parallel to the x-axis is in in the form of
1) x= some constant
or 2) y = some constant?
This is strike number 2 where you submitted posts with showing no work.
Try reading the forum's posting guidelines
Yes, the form is correct.so if I write it in slope-intercept form I get y = -(z+5)x/(z-3) + 8/(z-3) right?
Yes, to the second question. If the line is parallel to the x-axis i.e. the line [imath]y=0[/imath]. What is the slope?so if I write it in slope-intercept form I get y = -(z+5)x/(z-3) + 8/(z-3) right? and the slopes of parallel lines are the same aren't they?