wakeboarder08
New member
- Joined
- Feb 1, 2006
- Messages
- 1
how do i find the order pair (x,y)??
y=2x-4
2y=-x
y=2x-4
2y=-x
linear systems???
- Thread starter wakeboarder08
- Start date
Straight edge man
New member
- Joined
- Jan 31, 2006
- Messages
- 16
well there is more than one way... the first is graphing, in order to do that you have to get y by itself on both equations and then graph (a graphing calculator works best)
for example the first equation you get
y=2x-4
the second you would have to get y by itself you tell me... then you graph what y equals
here is a site you can do that [http://www.coolmath.com/graphit/?]
if you need more help pm me cuz i have to go bye...
for example the first equation you get
y=2x-4
the second you would have to get y by itself you tell me... then you graph what y equals
here is a site you can do that [http://www.coolmath.com/graphit/?]
if you need more help pm me cuz i have to go bye...
Straight edge man
New member
- Joined
- Jan 31, 2006
- Messages
- 16
well there is an easier way... it is called substitution... what you do is take one equation that is already set to y or x and then you replace it with the y or x on that equation...
for example-
y=2x-4, you take that and substitute it and the new equation would be 2(2x-4)=-x,
then you do distributive property so the equatoin would be 2x-8=-x
now you can solve for x.
then you solve for x and plug it in the y equation.
for example-
y=2x-4, you take that and substitute it and the new equation would be 2(2x-4)=-x,
then you do distributive property so the equatoin would be 2x-8=-x
now you can solve for x.
then you solve for x and plug it in the y equation.