Linear Programming: (7/10)x + y <= 630, (1/2)x + (5/6)y <= 600, x + (2/3)y <= 700,...

[Organon]

Linear Programming: (7/10)x + y <= 630, (1/2)x + (5/6)y <= 600, x + (2/3)y <= 700,...

I'm trying to solve a linear maximization program with the following constraints:

1) (7/10)x + y <= 630
2) (1/2)x + (5/6)y <= 600
3) x + (2/3)y <= 700
4) (1/10)x + (1/4)y <=135

I've simplified each equation to just be a y<= inequality and graphed it out on my TI84, but don't see an intersection point that indicates where the max value should be. I found elsewhere that the answer is (540, 252), but can't see how they got there.

Any help is appreciated.

 

[jtayag0622]

I'm trying to solve a linear maximization program with the following constraints:

1) (7/10)x + y <= 630
2) (1/2)x + (5/6)y <= 600
3) x + (2/3)y <= 700
4) (1/10)x + (1/4)y <=135

I've simplified each equation to just be a y<= inequality and graphed it out on my TI84, but don't see an intersection point that indicates where the max value should be. I found elsewhere that the answer is (540, 252), but can't see how they got there.

Any help is appreciated.

What's your maximization equation?

 

[Steven G]

I'm trying to solve a linear maximization program with the following constraints:

1) (7/10)x + y <= 630
2) (1/2)x + (5/6)y <= 600
3) x + (2/3)y <= 700
4) (1/10)x + (1/4)y <=135

I've simplified each equation to just be a y<= inequality and graphed it out on my TI84, but don't see an intersection point that indicates where the max value should be. I found elsewhere that the answer is (540, 252), but can't see how they got there.

Any help is appreciated.

Hi. To be honest I get real confused when things like this happen. You want us to help you but you fail to show us your work that is troubling you. If you can please supply us with your work, which is a forum rule--have you read them?, someone will help you see where you made your mistake. So please post back and we will help you figure this out. Thanks.

 

[Organon]

Sorry - new here and wasn't aware of the generally accepted practices.

The objective function is 10x + 9y

I actually just figured it out (something was off w/ my calculator), so nevermind. For future reference, though, is there a way to post screenshots from a graphing calculator (other than taking a pic w/ a phone) or would having written down the simplified inequality have sufficed for showing work? I may have more questions of this nature and don't want to be that person who serially posts questions in the wrong format.

Thanks, all!