Linear inequality + graphing?

[lcatherine24]

For this problem, I must find two points to plot in order to find the line.

The equation is: 3y-8x >24

So far, I have found that y=8 and x=-3.
The next step I must do is determine what type of line it is - solid or dashed. I believe it is dashed.
Where I am getting stick is where to shade on the graph - below or above the line. How do I go about figuring this portion of the question out?

If you catch any errors in my work, any help is appreciated. Thank you.

 

[tkhunny]

Many errors, sorry.

Points look like this (a,b) or (x,y) or (0,0) or (8,3). You have found none of these.

I recommend easy ones. This may be what you have done, but you have no communicated it well. I htink you may have meant (0,8) and (-3,0).

Solid or dashed is easy. If we ahve equality, it is solid. Your problem statement does not have equality, so it is dashed. Good work.

Shading isn't too tricky. Just try something. Really! Pick an easy point and try it out. I like (0,0) for anything that doesn't pass through the Origin.

4(0) - 8(0) = 0 > 24? No! Shade the side that does NOT contain the point (0,0).