Solve the following equations by using the substitution method; 2x+3y=2 3x-4y=20
G Guest Guest Dec 20, 2005 #1 Solve the following equations by using the substitution method; 2x+3y=2 3x-4y=20
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Dec 20, 2005 #2 2x+3y=2 x = (2-3y)/2 so 3x-4y=20 3(2-3y)/2-4y=20
O opticaltempest New member Joined Nov 19, 2005 Messages 48 Dec 20, 2005 #3 I worked through the problem on video for you. Feedback on the video is welcomed . It may take a few minutes to load on dial up.
I worked through the problem on video for you. Feedback on the video is welcomed . It may take a few minutes to load on dial up.
O opticaltempest New member Joined Nov 19, 2005 Messages 48 Dec 21, 2005 #4 Oops, I forgot the link to the video... http://www.badongo.com/vid.php?file...titution__2005-12-20_system+of+eqn+substi.wmv
Oops, I forgot the link to the video... http://www.badongo.com/vid.php?file...titution__2005-12-20_system+of+eqn+substi.wmv
G Guest Guest Dec 21, 2005 #5 I need hel on these three problems 1. y=2x+1 y=3x-1 2. x=-2/3y x-4 =-2/5(y+6) 3. 1/2(x-1)+1/39(y+2)=2 1/2x-1/4(y-4)=4 Thanks for helping me on the last problem.
I need hel on these three problems 1. y=2x+1 y=3x-1 2. x=-2/3y x-4 =-2/5(y+6) 3. 1/2(x-1)+1/39(y+2)=2 1/2x-1/4(y-4)=4 Thanks for helping me on the last problem.
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Dec 21, 2005 #6 What you posted are NOT the answers. You should end with x=? y=? Where ? is a real number. No variables. ----------------- Gene
What you posted are NOT the answers. You should end with x=? y=? Where ? is a real number. No variables. ----------------- Gene
G Guest Guest Dec 21, 2005 #7 These are the new problems I need help on 1. y=2x+1 y=3x-1 2. x=-2/3y x-4 =-2/5(y+6) 3. 1/2(x-1)+1/39(y+2)=2 1/2x-1/4(y-4)=4 Thanks for helping me on the last problem. These are the new problems I need help on
These are the new problems I need help on 1. y=2x+1 y=3x-1 2. x=-2/3y x-4 =-2/5(y+6) 3. 1/2(x-1)+1/39(y+2)=2 1/2x-1/4(y-4)=4 Thanks for helping me on the last problem. These are the new problems I need help on
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Dec 21, 2005 #8 New problems should be in a new thread. With the example of the first, you should be able to at least start on these. Please show your work. ------------------ Gene
New problems should be in a new thread. With the example of the first, you should be able to at least start on these. Please show your work. ------------------ Gene