Linear equation word problem

hem

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Mar 31, 2024
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The question and the answer to the question is said to be 'e'

My solution which i attempted was something like this

Let the number of 5 dollars be x
Number of 10 be 3x
And number of 20 be 1/3 *x which is is x/3

So 5.x+10. x. 3+20 . x/3=875

5x+30x+ 20x/3=875

35x . 3+ 20x/3- 125x



The ultimate answer is 875/125 which shows x is equal to 7 but the answer is something else can some please help?
 

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Last edited:
35x is multiplied by the denominator 3 so as to have the same denominator for both 35x and 20x and in order to add it to 20x which gives the result as 125x
That's not what you wrote; you didn't even write an equation.

Did you forget to multiply both sides by 3?
 
That's not what you wrote; you didn't even write an equation.

Did you forget to multiply both sides by 3?
Ill post a pic just some time, new to this site so might be a little handicapped in typing symbols appropriately apologies
 
Let the number of 5 dollars be x
Number of 10 be 3x
And number of 20 be 1/3 *x which is is x/3

So 5.x+10. x. 3+20 . x/3=875

5x+30x+ 20x/3=875

hem, a dot/decimal point is not a good symbol for use of a product. The integer constant immediately
next to the variable on its left side is sufficient to indicate the product. Your "let statements" need to
be accurate, consistent, and complete.

Let x = the number of $5 bills.
Let 3x = the number of $10 bills.
Let (1/3)x = x/3 = the number of $20 bills.

5(x) + 10(3x) + 20(x/3) = 875

5x + 30x + 20x/3 = 875
.
.
.
 
hem, a dot/decimal point is not a good symbol for use of a product. The integer constant immediately
next to the variable on its left side is sufficient to indicate the product. Your "let statements" need to
be accurate, consistent, and complete.

Let x = the number of $5 bills.
Let 3x = the number of $10 bills.
Let (1/3)x = x/3 = the number of $20 bills.

5(x) + 10(3x) + 20(x/3) = 875

5x + 30x + 20x/3 = 875
.
.
.
I am really sorry, new to this site will be more accurate henceforth.
 
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