Linear and Compuound Inequalities in Two variables

[icantdomath]

Hi. I'm in an Intermediate Algebra class in college. I'm having trouble with this problem. 2x is less or equal to -6y+12.
Could someone walk me through the first step?

 

[icantdomath]

Linear and Compound Inequalities

<= is symbol for less or equal; 2x <= -6y + 12
Start by dividing by 2:
x <= -3y + 6

Can you carry on?

If not, have a look here:
http://www.mathsisfun.com/algebra/inequality-solving.html

The answer I came to was x<= -3y/1 +6. So, -3y/1 (0,6)When I plot it it's totally different from the graph I have in my math book. I'm going to try this again. Thank you for answer in a timely manner.

 

[Quaid]

The answer I came to was x<= -3y/1 +6

When I plot it it's totally different from the graph I have in my math book.

You solved the inequality for x, instead of for y.

How are you plotting your result? Are you picking values for y, and then calculating the corresponding values of x?

The boundary of the solution region should be a solid line with negative slope, passing through y-intercept (0,2) and x-intercept (6,0). Is that what your book shows?

 

[stapel]

The answer I came to was x<= -3y/1 +6. So, -3y/1 (0,6)When I plot it it's totally different from the graph I have in my math book.

Start by solving for "y": 2x < -6y + 12 becomes x < -3y + 6 becomes 3y < -x + 6; divide through by 3 to finish.

Look at the associated equality, y = -(1/3)x + 2. Graph that line. Then shade the appropriate side of the line. Since the inequality is "y is LESS THAN", should you shade above ("greater than") or below ("less than") the line?