Linear Algebra

[javie almendo]

A certain three-digit number, N say, equals fifteen times
the sum of its digits. If its digits are reversed, the resulting
number exceeds N by 396. The one's digit is one larger
than the sum of the other two.
(a) Give a linear system of three equations whose three
unknowns are the digits of N.
(b) Solve the system and find N.


Thank you

 

[Deleted member 4993]

A certain three-digit number, N say, equals fifteen times
the sum of its digits. If its digits are reversed, the resulting
number exceeds N by 396. The one's digit is one larger
than the sum of the other two.
(a) Give a linear system of three equations whose three
unknowns are the digits of N.
(b) Solve the system and find N.


Thank you

The problem gives you clear instructions.

What have you done following those instructions?

Please share your work with us ...

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/th...Before-Posting

 

[stapel]

A certain three-digit number, N say, equals fifteen times the sum of its digits. If its digits are reversed, the resulting number exceeds N by 396. The one's digit is one larger than the sum of the other two.
(a) Give a linear system of three equations whose three unknowns are the digits of N.
(b) Solve the system and find N.

The trick is to use the digits (those being, as explained above, a, b, and c) to create the number, by using the meaning of place value. If N = 138, so a = 1, b = 3, and c = 8, then the expanded form would be N = 100*1 + 10*3 + 1*8 = 100a + 10b + 1c. Use "100a + 10b + 1c" for your system of equations. :wink: