Linear algebra

[unpaidactor]

Hi my question is how do I
Rewrite 2y = 6x + 18 in the form of w.x = 0 where w = [w₀ w₁ w₂], x = [1 x₁ x₂]



Thank you I would greatly appreciate it if anyone can help me I am so lost.

 

[Steven G]

I do not know hot write the vectors vertically, so I will write them horizontally. You should see them as vertical!

(18 6 -2) [math]\cdot[/math] (1 x y) = 0

 

[Dr.Peterson]

Hi my question is how do I
Rewrite 2y = 6x + 18 in the form of w.x = 0 where w = [w₀ w₁ w₂], x = [1 x₁ x₂]

View attachment 27666

Thank you I would greatly appreciate it if anyone can help me I am so lost.

I presume you know that the dot product w.x is w₀(1)+w₁x₁+w₂x₂.

If we let x₀ = x and x₁ = y, and write our equation in the form 6x-2y+18=0, what do the coefficients w_k have to be?

 

[topsquark]

I do not know hot write the vectors vertically, so I will write them horizontally. You should see them as vertical!

(18 6 -2) [math]\cdot[/math] (1 x y) = 0

Here's the LaTeX:
[math]\left ( \begin{matrix} 18 \\ 6 \\ -2 \end{matrix} \right )[/math]
-Dan

 

[unpaidactor]

Hi all! Thank you so much