peacefreak77
New member
- Joined
- Aug 22, 2006
- Messages
- 32
I hope this is the right forum to post this in.
Anyway, I don't know how to do this problem.
Find a linearly independent set of vectors that spans the same subspace of
(these are vectors) [[3][-2][-1]],[[3][-5][1]],[[0][-3][2]].
I think that these are linearly dependent vectors because there are infinite solutions to Ac=0 (if you consider A the matrix formed by these three vectors). Meaning I can use parameters and write the solutions for vector c.
Because these are linearly dependent vectors, I know they don't span all of R^3. But I don't know how to solve for exactly what B's (from Ac=B) they do span. Consequently, I don't know how to write an independent set of vectors that spans the same subspace, and I don't understand how an independent set of vectors could span the same specific subspace of a linearly dependent set of vectors, since 3 linearly independent vectors span all R^3.
I know the answer consists of 2 vectors with three componants, but I don't have any idea how to find the set they're asking for.
Anyway, I don't know how to do this problem.
Find a linearly independent set of vectors that spans the same subspace of
(these are vectors) [[3][-2][-1]],[[3][-5][1]],[[0][-3][2]].
I think that these are linearly dependent vectors because there are infinite solutions to Ac=0 (if you consider A the matrix formed by these three vectors). Meaning I can use parameters and write the solutions for vector c.
Because these are linearly dependent vectors, I know they don't span all of R^3. But I don't know how to solve for exactly what B's (from Ac=B) they do span. Consequently, I don't know how to write an independent set of vectors that spans the same subspace, and I don't understand how an independent set of vectors could span the same specific subspace of a linearly dependent set of vectors, since 3 linearly independent vectors span all R^3.
I know the answer consists of 2 vectors with three componants, but I don't have any idea how to find the set they're asking for.