Linear Algebra Plane Question

robbie

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The plane that passes through the point (3,5,2) and is perpendicular to both x+4z=0 and 5z(4x+5y)=7 has as its implicit equation.

How would you solve this? This is Linear Algebra I think.
 
The plane that passes through the point (3,5,2) and is perpendicular to both x+4z=0 and 5z(4x+5y)=7 has as its implicit equation.
Rewrite 5z(4x+5y)=7\displaystyle 5z-(4x+5y)=-7 as 4x+5y5z=7\displaystyle 4x+5y-5z=7. The norma is <1,0,4>×<4,5,5>\displaystyle <1,0,4>\times <4,5,-5>.
See here,
 
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