Find the values of k so that the lines described by 2x-3y=12 and kx+6y=48 are parallel.
==========
First write each line in y=mx+b form to see the slope of each:
2x - 3y = 12 ---> y = (-2x + 12)/-3 ---> y = (2/3)x - 4 [slope is 2/3]
kx + 6y = 48 ---> y = (-kx + 48)/6 ---> y = (-k/6)x + 8 [slope is -k/6]
To be parallel, the slopes must be equal, so:
2/3 = -k/6
k = -4
Hope that helps...
Steve
