line integral: int [x - y + z - 2) ds, where C is segment...

[cheffy]

evaluate
$\displaystyle \int\limits_C {(x - y + z - 2)ds}$
where C is the straight line segment x=t, y=(1-t), z=1 from (0,1,1) to (1,0,1).

I'm getting really confused as to where and how the two points factor into this. Either that or how the 3 equations do. Or both.

 

[stapel]

... the straight line segment x=t, y=(1-t), z=1 from (0,1,1) to (1,0,1).

I'm getting really confused as to where and how the two points factor into this..

What is the t-value that gives you the first point? What t-value gives you the second point? :wink:

Eliz.

 

[Unco]

The curve is already parameterised, and Eliz has pointed to the limits, so all that is left is to rewrite the integral with respect to t - remembering ds = ||dr/dt||*dt.