:? :? How do I get the x # in x+y=10 or y=x+10? Also I need help with like y=15/8+b. I do okay until I get to something b=9-15/8*4. How do you get y=15/8x+3/2 from that?
For \(\displaystyle 1\), Subtract \(\displaystyle y\) from both sides of the equations which "balances" it because you did the same thing to both sides of the equation.
My problem is trying to find the right #'s to be able to graph two and three points that are on the have slope. Can I pick just any #'s? I'ts been awhile since I've been in school but I don't remember graphing being this complicated.
So you're studying math on your own? Good for you :idea:
"How do I get the x # in x+y=10"
So you're asking: if I let x = a number, say 4, how do I "put it" in the equation?
Very simple; replace the x with 4: 4 + y = 10
The you can solve for y:
y = 10 - 4
y = 6
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