Limits

[ELRA0098321]

Given that:
the limit of f(x) as x approaches 5 equals 5 , the limit of g(x) as x approaches 5 equals negative 2 , the limit of h(x) as x approaches 5 equals 3

Evaluate the following:
the limit as x approaches five [2 + square root 4 - g(x)]
I need help! I don't know how to start the problem.

Thanks for the help!

 

[pka]

Given that:
the limit of f(x) as x approaches 5 equals 5 , the limit of g(x) as x approaches 5 equals negative 2 , the limit of h(x) as x approaches 5 equals 3

Evaluate the following:
the limit as x approaches five [2 + square root 4 - g(x)]
I need help! I don't know how to start the problem.

It is hard to read what you posted.

Is it \(\displaystyle \displaystyle{\lim _{x \to 5}}\left( {2 + \sqrt {4 - g(x)} } \right)\text{ or }{\lim _{x \to 5}}\left( {2 + \sqrt 4 - g(x)} \right)\)

 

[ELRA0098321]

It is hard to read what you posted.

Is it \(\displaystyle \displaystyle{\lim _{x \to 5}}\left( {2 + \sqrt {4 - g(x)} } \right)\text{ or }{\lim _{x \to 5}}\left( {2 + \sqrt 4 - g(x)} \right)\)

Yes it is the first one. I'm still trying to figure out what latex code to use and how to use it to make it look like that. Sorry.

 

[pka]

Yes it is the first one. I'm still trying to figure out what latex code to use and how to use it to make it look like that. Sorry.

Here is a hint: by continuity, \(\displaystyle {\displaystyle\lim _{x \to 5}}\left( {\sqrt {4 - g(x)} } \right) = \sqrt 6 \)

If you click "REPLY WITH QUOTE" you can see the LaTeX code.

 

[ELRA0098321]

Here is a hint: by continuity, \(\displaystyle {\displaystyle\lim _{x \to 5}}\left( {\sqrt {4 - g(x)} } \right) = \sqrt 6 \)

If you click "REPLY WITH QUOTE" you can see the LaTeX code.

Oh ok I saw that. Thanks for the hint.