limits

schefflw said:
what is the limit of x as its approaches 2?

x^2 - x -2 / x - 2

The expression in your post translates to:

\(\displaystyle x^2 \ - \ x \ - \ \frac{2}{x} \ - \ 2\)

However if you wanted to write:

\(\displaystyle \frac{x^2 \ - \ x \ - \ 2}{x \ - \ 2}\)

you should have written

(x^2 - x -2 )/ (x - 2) ... watch the use of parenthesis (PEMDAS) as grouping symbol

Now edit your post as necessary.
 
schefflw said:
what is the limit of x as its approaches 2?

x^2 - x -2 / x - 2

use l'hospital rule and simply take dx of the num and dem of the function until you can plug in 2 such that the function is continuous
 
vouslavous said:
schefflw said:
what is the limit of x as its approaches 2?

x^2 - x -2 / x - 2

use l'hospital rule and simply take dx of the num and dem of the function until you can plug in 2 such that the function is continuous

I'm sure schefflw is in intro calc and is expected to factor and what not.

\(\displaystyle \lim_{x \to 2}\frac{x^2 \ - \ x \ - \ 2}{x \ - \ 2}\)

\(\displaystyle =\lim_{x \to 2}\frac{(x-2)(x+1)}{(x-2)}\)

etc.....
 
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