LIMITS!

G

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lim (3/n)
n-> (infinite)


find the limit by using properities of limits
 
alohagrlxo said:
find the limit by using properities of limits
What "properties" have you been given? For instance, have you been given any rules regarding the limit of 1/n as n gets arbitrarily large ("goes to infinity")?

Thank you.

Eliz.
 
nevermind i figured it out

but here's another question

find the limit of the sequence of decimals formed by an increasing number of 3s: .3, .33, .333, .3333, .33333......
 
Hello, alohagrlxo!

Find the limit of the sequence of decimals formed by an increasing number of 3s:
\(\displaystyle \;\;\;0.3,\;0.33,\;0.333,\;0.3333,\;0.33333,\;\cdots\)
The number is of the form: \(\displaystyle \,S\;=\;\frac{3}{10}\,+\,\frac{3}{10^2}\,+\,\frac{3}{10^3} \,+\,\frac{3}{10^4}\,+\,\cdots\)

This is an infinite geometric series with first term \(\displaystyle a=\frac{3}{10}\) and common ratio \(\displaystyle r = \frac{1}{10}\)

The sum is: \(\displaystyle \L\,S\;=\;\frac{\frac{3}{10}}{1\,-\,\frac{1}{10}} \;=\;\frac{\frac{30}{10}}{\frac{9}{10}}\;=\;\frac{1}{3}\)
 
alohagrlxo said:
here's another question
In the future, please post new questions as new threads, not as replies to old threads, where they are frequently over-looked. Thank you.

alohagrlxo said:
find the limit of the sequence of decimals formed by an increasing number of 3s: .3, .33, .333, .3333, .33333......
Hint: Consider geometric series.

Eliz.
 
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