limits

[xc630]

Hi I am having trouble with this one problem. I have to evaluate the given limit or state that the limit does not exist. Or if the sequence apporaches infinity or negative infinity, so state.

lim e^-n

(Under there is a: n arrow infinity)

With regaular numbers I think the limit would be zero but I do not rememer what the e stands for. Alll I know is it has something to do with natural logs. Thanks for any help. You guys are the best!

 

[Daniel_Feldman]

e is approximately 2.72.

e^-n=1/e^n

As n goes to infinity, e^n gets infinitely big, so 1/e^n gets infinitely small (but stays greater than 0). So the answer is 0.