limits

[lotmasta]

I just need a clarification on a limit:

lim              (x-2)
x->2          -------------
                  1/x - 1/2

So that would be (x-2)^2 correct? If I attempt to solve a limit that way,
does anyone know why it doesn't work? because without graphing it would appear that the limit would be 0.

 

[stapel]

So that would be (x-2)^2 correct?

What would be (x - 2)²?

If I attempt to solve a limit that way...

Which way?

I'm sorry, but I don't understand your somewhat cryptic post. Please reply with clarification, including the method (or "way") you are supposed to be using for finding the limit. Thank you.

Eliz.

 

[lotmasta]

For (x-2)^2 I just mean that the original limit could also be written as:
lim (x-2)^2
x->2

The method for solving the limit is what I'm not really sure about because

(2-2)^2 = 0 and that is incorrect. The limit is -4 but the way to actually get the correct limit is sketchy for me unless I graph it or put in the numbers approaching 2 manually.