How would I solve this limit: lim 1 -cos (x) / sin² x x?0 Thank you :) :D
T temporaryinsanit New member Joined Feb 20, 2010 Messages 10 Feb 21, 2010 #1 How would I solve this limit: lim 1 -cos (x) / sin² x x?0 Thank you
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Feb 21, 2010 #2 \(\displaystyle \lim_{x\to0}\frac{1-cos(x)}{sin^{2}(x)} \ gives \ the \ indeterminate \ form \ \frac{0}{0}.\) \(\displaystyle Sounds \ like \ a \ job \ for \ the \ Marqui.\)
\(\displaystyle \lim_{x\to0}\frac{1-cos(x)}{sin^{2}(x)} \ gives \ the \ indeterminate \ form \ \frac{0}{0}.\) \(\displaystyle Sounds \ like \ a \ job \ for \ the \ Marqui.\)
T temporaryinsanit New member Joined Feb 20, 2010 Messages 10 Feb 21, 2010 #3 Since it gives the intermediate form does that mean I have to use L' Hoptials Rule
B BigGlenntheHeavy Senior Member Joined Mar 8, 2009 Messages 1,577 Feb 21, 2010 #4 \(\displaystyle You \ can \ use \ whatever \ your \ heart \ desires, \as \ long \ as \ you \ come \ up \ with \ the \ correct \ answer.\)
\(\displaystyle You \ can \ use \ whatever \ your \ heart \ desires, \as \ long \ as \ you \ come \ up \ with \ the \ correct \ answer.\)
S swaroop New member Joined Feb 1, 2010 Messages 28 Feb 22, 2010 #5 In limits whenever there is a form 0/0 or Inf/Inf, you need to apply l'hoptial rule. So need to diff oth numerator and denom and evaluate
In limits whenever there is a form 0/0 or Inf/Inf, you need to apply l'hoptial rule. So need to diff oth numerator and denom and evaluate