limits, asymptotes and graphs, fcn for brine concentration

FrostedMango

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Sep 2, 2007
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3
First Problem: Can the graph of y = f(x) intersect a vertical asmptote? Can it intersect a horizontal asymptote? How many asymptotes can the graph of y = f(x) have? Sketch.

The part I didn't understand was y = f(x), wouldn't this simply be saying y = y, well that's how I thought it and which in that case, the graph isn't exactly a graph anymore... so can someone help me to understand what y = f(x) is suppose to mean?

Second problem: Find lim [x -> infinity] cos(x)

the part i was confused at was that as "x" approaches infinite, the graph just keeps on going up and down between y = 1 and -1. So does that mean there is no limit or if so, how do we illustrate a limit where there are two of them?

Third problem: A tank contains 5000L of pure water. Brine that contains 30g of salt per liter of water is pumped into the tank at a rate of 25L/min. Show that the concentration of salt after t minutes (in grams per liter) is: C(t) = 30t/(200+t)

The part I'm confused at was... well pretty much the question itself. It told me to show that the equation is correct (i think), but I didn't understand the quesoitn at all. So is it asking if that equation is right and prove it by just plugging in random values into it or waht is it asking?

Fourth problem: Find lim [x -> -infinity] sqrt(x^2 + x + 1) + x

ok, so I tried it out and I got a wrong answer, i ended up with DNE, can you tell me where I went wrong if you can? so this is what i did: (by the way, the question actually was in 3 parts, first 2 which of finding the limit and third, which is what I'm doing now is to prove it)

1. (sqrt(x^2 + x + 1) + x) * (sqrt(x^2 + x + 1) - x)/(sqrt(x^2 + x + 1) - x)
2. (x + 1) / (sqrt(x^2 + x + 1) - x)
3. (x/x + 1/x) / (-sqrt(x^2 + x + 1)/sqrt(x^2)) - x/x
4. (1 + 1/x) / -sqrt(1 + 1/x + 1/x^2) - 1
Since x is to negative infinite, 1/x, 1/x^2 become insignificant, so I considered them to be 0
5. -1 / sqrt(1) - 1
6. -1 / 1 - 1 = -1 / 0 = DNE
 
#2. You're correct. Because it oscillates back and forth, it is stated as having no limit.

#3. The amount of salt in the tank at any time t is 750t, because

\(\displaystyle \L\\\left(30 \;\ \frac{grams}{L}\right)\left(25 \;\ \frac{L}{min}\right)=750 \;\ \frac{grams}{min}\)

Since it's not flowing out, the water is building up at 5000+25t L/min.

The concentration of salt in the tank is, therefore, \(\displaystyle \L\\\frac{750t}{5000+25t}\)

What does this reduce to?


#4:

You done OK by multiplying by the conjugate.

It is helpful to manipulate the function so the powers of x become powers of 1/x. This can be done by dividing the numerator and denominator by |x| and using the fact that \(\displaystyle \sqrt{x^{2}}=|x|\).
As \(\displaystyle x\rightarrow{-\infty}\), the values of x are eventually negative, so we can replace |x| with -x where we so desire.

\(\displaystyle \L\\\lim_{x\rightarrow{-\infty}}\frac{x+1}{\sqrt{x^{2}+x+1}-x}\)

Divide by \(\displaystyle x^{2}\) in the radical and divide by -x outside.

\(\displaystyle \L\\\lim_{x\rightarrow{-\infty}}\frac{-1-\frac{1}{x}}{\sqrt{1+\frac{1}{x^{2}}+\frac{1}{x^{2}}}+1}\)

Now, see the limit?
 
Re: limits, asymptotes and graphs, fcn for brine concentrati

FrostedMango said:
First Problem: Can the graph of y = f(x) intersect a vertical asmptote? Can it intersect a horizontal asymptote? How many asymptotes can the graph of y = f(x) have? Sketch.

The part I didn't understand was y = f(x), wouldn't this simply be saying y = y, well that's how I thought it and which in that case, the graph isn't exactly a graph anymore... so can someone help me to understand what y = f(x) is suppose to mean?
Code:
y = x^2

y = ln(x) + sin(x)
above are all in general represented as y = f(x)
 
Thanks a lot, #2 was sort of confusing... and #4, I figured out why I was all confused up, the negative sign kept on tricking me a bit.
#3, ok that took me a while to think but I think I get it, thanks a lot!

well for #1, i really don't it's possible to hit any asyntopes if y = f(x) because well... then it's just y = whatever the function is, which means it still makes its asymtopes and never reach it...
 
FrostedMango said:
Thanks a lot, #2 was sort of confusing... and #4, I figured out why I was all confused up, the negative sign kept on tricking me a bit.
#3, ok that took me a while to think but I think I get it, thanks a lot!

well for #1, i really don't it's possible to hit any asyntopes if y = f(x) because well... then it's just y = whatever the function is, which means it still makes its asymtopes and never reach it...

y = f(x) can intersect a horizontal asymptote - but not a vertical one.
 
yes, thanks a lot
I figured it out a little ealier but forgot to come to the site... thanks a lot to everyone
 
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